-16p=20p^2

Solution for -16p=20p^2 equation:

-16p=20p^2

We move all terms to the left:

-16p-(20p^2)=0

determiningTheFunctionDomain
-20p^2-16p=0

a = -20; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·(-20)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*-20}=\frac{0}{-40}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*-20}=\frac{32}{-40}
=-4/5
$